Validate phone number with JavaScript

0 votes
asked Dec 2, 2010 by castro-roy

I found this code in some website, and it works perfectly. It validates that the phone number is in one of these formats:
(123) 456-7890 or 123-456-7890

The problem is that my client (I don't know why, maybe client stuffs) wants to add another format, the ten numbers consecutively, something like this: 1234567890.

I'm using this regular expression,


How can I add that it also validates the another format? I'm not good with regular expressions.

17 Answers

0 votes
answered Dec 2, 2010 by luc-veronneau

I have to agree that validating phone numbers is a difficult task. As for this specific problem i would change the regex from




as the only one more element that becomes unnecessary is the last dash/space.

0 votes
answered Dec 2, 2010 by donut

This will work:


The ? character signifies that the preceding group should be matched zero or one times. The group (-|\s) will match either a - or a | character. Adding ? after the second occurrence of this group in your regex allows you to match a sequence of 10 consecutive digits.

0 votes
answered Dec 2, 2010 by josh3736

First off, your format validator is obviously only appropriate for NANP (country code +1) numbers. Will your application be used by someone with a phone number from outside North America? If so, you don't want to prevent those people from entering a perfectly valid [international] number.

Secondly, your validation is incorrect. NANP numbers take the form NXX NXX XXXX where N is a digit 2-9 and X is a digit 0-9. Additionally, area codes and exchanges may not take the form N11 (end with two ones) to avoid confusion with special services except numbers in a non-geographic area code (800, 888, 877, 866, 855, 900) may have a N11 exchange.

So, your regex will pass the number (123) 123 4566 even though that is not a valid phone number. You can fix that by replacing \d{3} with [2-9]{1}\d{2}.

Finally, I get the feeling you're validating user input in a web browser. Remember that client-side validation is only a convenience you provide to the user; you still need to validate all input (again) on the server.

TL;DR don't use a regular expression to validate complex real-world data like phone numbers or URLs. Use a specialized library.

0 votes
answered Dec 2, 2010 by paul-schreiber

What I would do is ignore the format and validate the numeric content:

var originalPhoneNumber = "415-555-1212";

function isValid(p) {
  var phoneRe = /^[2-9]\d{2}[2-9]\d{2}\d{4}$/;
  var digits = p.replace(/\D/g, "");
  return phoneRe.test(digits);
0 votes
answered Dec 2, 2010 by 6502

I would suggest using something clearer (especially thinking to who will have to maintain the code)... what about:

var formats = "(999)999-9999|999-999-9999|9999999999";
var r = RegExp("^(" +
                 .replace(/([\(\)])/g, "\\$1")
                 .replace(/9/g,"\\d") +

where the regexp is built from a clear template ? Adding a new one would then be a no-brainer and may be even the customer itself could be able to do that in a "options" page.

0 votes
answered Dec 2, 2010 by kennebec

If you are looking for 10 and only 10 digits, ignore everything but the digits-

   return value.match(/\d/g).length===10;
0 votes
answered Dec 2, 2011 by billbad

The following REGEX will validate any of these formats:

(123) 456-7890

0 votes
answered Dec 20, 2011 by g1smd

Javascript telephone number parser with metadata for more than 200 countries:

0 votes
answered Dec 12, 2013 by parijat


The ? character signifies that the preceding group should be matched zero or one times. The group (-|\s) will match either a - or a | character.

0 votes
answered Dec 25, 2013 by erasmus

Everyone's answers are great, but here's one I think is a bit more comprehensive...

This is written for javascript match use of a single number in a single line:

^(?!.*911.*\d{4})((\+?1[\/ ]?)?(?![\(\. -]?555.*)\( ?[2-9][0-9]{2} ?\) ?|(\+?1[\.\/ -])?[2-9][0-9]{2}[\.\/ -]?)(?!555.?01..)([2-9][0-9]{2})[\.\/ -]?([0-9]{4})$

If you want to match at word boundaries, just change the ^ and $ to \b

I welcome any suggestions, corrections, or criticisms of this solution. As far as I can tell, this matches the NANP format (for USA numbers - I didn't validate other North American countries when creating this), avoids any 911 errors (can't be in the area code or region code), eliminates only those 555 numbers which are actually invalid (region code of 555 followed by 01xx where x = any number).

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